312114121411181 has 2 divisors, whose sum is σ = 312114121411182. Its totient is φ = 312114121411180.

The previous prime is 312114121411163. The next prime is 312114121411241. The reversal of 312114121411181 is 181114121411213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 311853348796900 + 260772614281 = 17659370^2 + 510659^2 .

It is a cyclic number.

It is not a de Polignac number, because 312114121411181 - 2²² = 312114117216877 is a prime.

It is a super-2 number, since 2×312114121411181² (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312114121417181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156057060705590 + 156057060705591.

It is an arithmetic number, because the mean of its divisors is an integer number (156057060705591).

Almost surely, 2^{312114121411181} is an apocalyptic number.

It is an amenable number.

312114121411181 is a deficient number, since it is larger than the sum of its proper divisors (1).

312114121411181 is an equidigital number, since it uses as much as digits as its factorization.

312114121411181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1536, while the sum is 32.

Adding to 312114121411181 its sum of digits (32), we get a palindrome (312114121411213).

Adding to 312114121411181 its reverse (181114121411213), we get a palindrome (493228242822394).

The spelling of 312114121411181 in words is "three hundred twelve trillion, one hundred fourteen billion, one hundred twenty-one million, four hundred eleven thousand, one hundred eighty-one".