Base | Representation |
---|---|
bin | 101101011010110011110… |
… | …100000001000000000011 |
3 | 102001101021012212010102121 |
4 | 231122303310001000003 |
5 | 402114120212423042 |
6 | 10345501551225111 |
7 | 441332220612223 |
oct | 55326364010003 |
9 | 12041235763377 |
10 | 3121163014147 |
11 | aa3750175612 |
12 | 424a9b218197 |
13 | 19842a95bb09 |
14 | ab0ca8a2083 |
15 | 562c687b367 |
hex | 2d6b3d01003 |
3121163014147 has 2 divisors, whose sum is σ = 3121163014148. Its totient is φ = 3121163014146.
The previous prime is 3121163014117. The next prime is 3121163014219. The reversal of 3121163014147 is 7414103611213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3121163014147 - 27 = 3121163014019 is a prime.
It is a super-2 number, since 2×31211630141472 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3121163014117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560581507073 + 1560581507074.
It is an arithmetic number, because the mean of its divisors is an integer number (1560581507074).
Almost surely, 23121163014147 is an apocalyptic number.
3121163014147 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121163014147 is an equidigital number, since it uses as much as digits as its factorization.
3121163014147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 34.
The spelling of 3121163014147 in words is "three trillion, one hundred twenty-one billion, one hundred sixty-three million, fourteen thousand, one hundred forty-seven".
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