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3121163014147 is a prime number
BaseRepresentation
bin101101011010110011110…
…100000001000000000011
3102001101021012212010102121
4231122303310001000003
5402114120212423042
610345501551225111
7441332220612223
oct55326364010003
912041235763377
103121163014147
11aa3750175612
12424a9b218197
1319842a95bb09
14ab0ca8a2083
15562c687b367
hex2d6b3d01003

3121163014147 has 2 divisors, whose sum is σ = 3121163014148. Its totient is φ = 3121163014146.

The previous prime is 3121163014117. The next prime is 3121163014219. The reversal of 3121163014147 is 7414103611213.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3121163014147 - 27 = 3121163014019 is a prime.

It is a super-2 number, since 2×31211630141472 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3121163014117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560581507073 + 1560581507074.

It is an arithmetic number, because the mean of its divisors is an integer number (1560581507074).

Almost surely, 23121163014147 is an apocalyptic number.

3121163014147 is a deficient number, since it is larger than the sum of its proper divisors (1).

3121163014147 is an equidigital number, since it uses as much as digits as its factorization.

3121163014147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 34.

The spelling of 3121163014147 in words is "three trillion, one hundred twenty-one billion, one hundred sixty-three million, fourteen thousand, one hundred forty-seven".