Base | Representation |
---|---|
bin | 1110001100011000111001… |
… | …11101011010001001101001 |
3 | 11002111211122212100122210001 |
4 | 13012030130331122021221 |
5 | 13042334200334344402 |
6 | 150214333444223001 |
7 | 6400664532534001 |
oct | 706143475321151 |
9 | 132454585318701 |
10 | 31212013199977 |
11 | 9a43a38835095 |
12 | 360112009aa61 |
13 | 14553848309bc |
14 | 79c95316b001 |
15 | 391d69491187 |
hex | 1c631cf5a269 |
31212013199977 has 2 divisors, whose sum is σ = 31212013199978. Its totient is φ = 31212013199976.
The previous prime is 31212013199923. The next prime is 31212013199987. The reversal of 31212013199977 is 77999131021213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21257300398096 + 9954712801881 = 4610564^2 + 3155109^2 .
It is a cyclic number.
It is not a de Polignac number, because 31212013199977 - 223 = 31212004811369 is a prime.
It is not a weakly prime, because it can be changed into another prime (31212013199987) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606006599988 + 15606006599989.
It is an arithmetic number, because the mean of its divisors is an integer number (15606006599989).
Almost surely, 231212013199977 is an apocalyptic number.
It is an amenable number.
31212013199977 is a deficient number, since it is larger than the sum of its proper divisors (1).
31212013199977 is an equidigital number, since it uses as much as digits as its factorization.
31212013199977 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1285956, while the sum is 55.
The spelling of 31212013199977 in words is "thirty-one trillion, two hundred twelve billion, thirteen million, one hundred ninety-nine thousand, nine hundred seventy-seven".
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