Base | Representation |
---|---|
bin | 1110001100011001000100… |
… | …10000100111101000001111 |
3 | 11002111211220001200100212021 |
4 | 13012030202100213220033 |
5 | 13042334341120400444 |
6 | 150214350342151011 |
7 | 6400666662416611 |
oct | 706144220475017 |
9 | 132454801610767 |
10 | 31212102121999 |
11 | 9a43a83a4a567 |
12 | 3601145a22467 |
13 | 145539a096096 |
14 | 79c960cb6db1 |
15 | 391d721a8584 |
hex | 1c6322427a0f |
31212102121999 has 2 divisors, whose sum is σ = 31212102122000. Its totient is φ = 31212102121998.
The previous prime is 31212102121961. The next prime is 31212102122017. The reversal of 31212102121999 is 99912120121213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31212102121999 - 211 = 31212102119951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31212102121099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606051060999 + 15606051061000.
It is an arithmetic number, because the mean of its divisors is an integer number (15606051061000).
Almost surely, 231212102121999 is an apocalyptic number.
31212102121999 is a deficient number, since it is larger than the sum of its proper divisors (1).
31212102121999 is an equidigital number, since it uses as much as digits as its factorization.
31212102121999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 43.
The spelling of 31212102121999 in words is "thirty-one trillion, two hundred twelve billion, one hundred two million, one hundred twenty-one thousand, nine hundred ninety-nine".
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