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31213004114 = 215606502057
BaseRepresentation
bin11101000100011100…
…001010010101010010
32222120021202220012102
4131010130022111102
51002411012112424
622201123000402
72153326104665
oct350434122522
988507686172
1031213004114
1112267a21a76
126071209102
132c35790606
1417215a16dc
15c2a3827ae
hex74470a552

31213004114 has 4 divisors (see below), whose sum is σ = 46819506174. Its totient is φ = 15606502056.

The previous prime is 31213004113. The next prime is 31213004161. The reversal of 31213004114 is 41140031213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41140031213 = 337112204103.

It can be written as a sum of positive squares in only one way, i.e., 17697779089 + 13515225025 = 133033^2 + 116255^2 .

It is not an unprimeable number, because it can be changed into a prime (31213004113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7803251027 + ... + 7803251030.

Almost surely, 231213004114 is an apocalyptic number.

31213004114 is a deficient number, since it is larger than the sum of its proper divisors (15606502060).

31213004114 is a wasteful number, since it uses less digits than its factorization.

31213004114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15606502059.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 31213004114 its reverse (41140031213), we get a palindrome (72353035327).

The spelling of 31213004114 in words is "thirty-one billion, two hundred thirteen million, four thousand, one hundred fourteen".

Divisors: 1 2 15606502057 31213004114