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312130113 = 3372811983
BaseRepresentation
bin10010100110101…
…011101001000001
3210202022212000120
4102212223221001
51114401130423
650550010453
710510030221
oct2246535101
9722285016
10312130113
11150209a79
1288646a29
134c887099
142d650081
151c607ee3
hex129aba41

312130113 has 8 divisors (see below), whose sum is σ = 427421568. Its totient is φ = 202462704.

The previous prime is 312130109. The next prime is 312130121. The reversal of 312130113 is 311031213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 312130113 - 22 = 312130109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312130092 and 312130101.

It is not an unprimeable number, because it can be changed into a prime (312130193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1405881 + ... + 1406102.

It is an arithmetic number, because the mean of its divisors is an integer number (53427696).

Almost surely, 2312130113 is an apocalyptic number.

It is an amenable number.

312130113 is a deficient number, since it is larger than the sum of its proper divisors (115291455).

312130113 is a wasteful number, since it uses less digits than its factorization.

312130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2812023.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 312130113 is about 17667.2044477897. The cubic root of 312130113 is about 678.3365576994.

Adding to 312130113 its reverse (311031213), we get a palindrome (623161326).

The spelling of 312130113 in words is "three hundred twelve million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 37 111 2811983 8435949 104043371 312130113