Base | Representation |
---|---|
bin | 1110001100011010110011… |
… | …01101010110010011101111 |
3 | 11002111221021220011101112011 |
4 | 13012031121231112103233 |
5 | 13042343242243300421 |
6 | 150215022533222051 |
7 | 6401032016562652 |
oct | 706153155262357 |
9 | 132457256141464 |
10 | 31213032400111 |
11 | 9a44411082251 |
12 | 3601365491927 |
13 | 14554b7a311c3 |
14 | 79ca0c675899 |
15 | 391dc8bb64e1 |
hex | 1c6359b564ef |
31213032400111 has 2 divisors, whose sum is σ = 31213032400112. Its totient is φ = 31213032400110.
The previous prime is 31213032400097. The next prime is 31213032400139. The reversal of 31213032400111 is 11100423031213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31213032400111 - 227 = 31212898182383 is a prime.
It is a super-2 number, since 2×312130324001112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31213032400171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606516200055 + 15606516200056.
It is an arithmetic number, because the mean of its divisors is an integer number (15606516200056).
Almost surely, 231213032400111 is an apocalyptic number.
31213032400111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31213032400111 is an equidigital number, since it uses as much as digits as its factorization.
31213032400111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 31213032400111 its reverse (11100423031213), we get a palindrome (42313455431324).
The spelling of 31213032400111 in words is "thirty-one trillion, two hundred thirteen billion, thirty-two million, four hundred thousand, one hundred eleven".
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