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31213112000302 = 215606556000151
BaseRepresentation
bin1110001100011010111100…
…11100111111111100101110
311002111221111102221111110101
413012031132130333330232
513042343423133002202
6150215034455301314
76401034004302331
oct706153634777456
9132457442844411
1031213112000302
119a44452000031
12360138807a83a
1314554cb3815cb
1479ca19076618
15391dd0b8b887
hex1c635e73ff2e

31213112000302 has 4 divisors (see below), whose sum is σ = 46819668000456. Its totient is φ = 15606556000150.

The previous prime is 31213112000293. The next prime is 31213112000339. The reversal of 31213112000302 is 20300021131213.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 31213112000302.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7803278000074 + ... + 7803278000077.

It is an arithmetic number, because the mean of its divisors is an integer number (11704917000114).

Almost surely, 231213112000302 is an apocalyptic number.

31213112000302 is a deficient number, since it is larger than the sum of its proper divisors (15606556000154).

31213112000302 is a wasteful number, since it uses less digits than its factorization.

31213112000302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15606556000153.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 31213112000302 its reverse (20300021131213), we get a palindrome (51513133131515).

The spelling of 31213112000302 in words is "thirty-one trillion, two hundred thirteen billion, one hundred twelve million, three hundred two", and thus it is an aban number.

Divisors: 1 2 15606556000151 31213112000302