Base | Representation |
---|---|
bin | 100011011111000011011110… |
… | …1101010000110001100010010 |
3 | 1111221011110112202211202011221 |
4 | 1012332012331222012030102 |
5 | 311402424441044401232 |
6 | 3023503054055155254 |
7 | 122513513405161204 |
oct | 10676067552061422 |
9 | 1457143482752157 |
10 | 312131340231442 |
11 | 9050018134a146 |
12 | 2b01118a375b2a |
13 | 10521b2254c184 |
14 | 57113478b4774 |
15 | 26143bc0cd897 |
hex | 11be1bda86312 |
312131340231442 has 8 divisors (see below), whose sum is σ = 476132552895600. Its totient is φ = 153420489266244.
The previous prime is 312131340231413. The next prime is 312131340231521. The reversal of 312131340231442 is 244132043131213.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 312131340231398 and 312131340231407.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1322590424592 + ... + 1322590424827.
It is an arithmetic number, because the mean of its divisors is an integer number (59516569111950).
Almost surely, 2312131340231442 is an apocalyptic number.
312131340231442 is a deficient number, since it is larger than the sum of its proper divisors (164001212664158).
312131340231442 is a wasteful number, since it uses less digits than its factorization.
312131340231442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2645180849480.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 312131340231442 its reverse (244132043131213), we get a palindrome (556263383362655).
The spelling of 312131340231442 in words is "three hundred twelve trillion, one hundred thirty-one billion, three hundred forty million, two hundred thirty-one thousand, four hundred forty-two".
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