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312131401400401 = 1122579598358681
BaseRepresentation
bin100011011111000011100000…
…1010011011100000001010001
31111221011110201000221110012221
41012332013001103130001101
5311402430102224303101
63023503104122221041
7122513515050124312
oct10676070123340121
91457143630843187
10312131401400401
1190500202929300
122b0111a6954781
1310521b3211821b
145711351a78609
1526143c2662aa1
hex11be1c14dc051

312131401400401 has 6 divisors (see below), whose sum is σ = 343086581704706. Its totient is φ = 283755819454800.

The previous prime is 312131401400359. The next prime is 312131401400407. The reversal of 312131401400401 is 104004104131213.

It can be written as a sum of positive squares in only one way, i.e., 177638116329025 + 134493285071376 = 13328095^2 + 11597124^2 .

It is not a de Polignac number, because 312131401400401 - 229 = 312130864529489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312131401400407) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1289799179220 + ... + 1289799179461.

Almost surely, 2312131401400401 is an apocalyptic number.

It is an amenable number.

312131401400401 is a deficient number, since it is larger than the sum of its proper divisors (30955180304305).

312131401400401 is a wasteful number, since it uses less digits than its factorization.

312131401400401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2579598358703 (or 2579598358692 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 312131401400401 its reverse (104004104131213), we get a palindrome (416135505531614).

The spelling of 312131401400401 in words is "three hundred twelve trillion, one hundred thirty-one billion, four hundred one million, four hundred thousand, four hundred one".

Divisors: 1 11 121 2579598358681 28375581945491 312131401400401