Base | Representation |
---|---|
bin | 100011011111000011110110… |
… | …0111000000110100011100111 |
3 | 1111221011112120222111201012011 |
4 | 1012332013230320012203213 |
5 | 311402433101400311403 |
6 | 3023503304434535051 |
7 | 122513542134602134 |
oct | 10676075470064347 |
9 | 1457145528451164 |
10 | 312132132432103 |
11 | 90500548543235 |
12 | 2b01136b737487 |
13 | 10521c1a701069 |
14 | 57113c0bad58b |
15 | 2614416914a6d |
hex | 11be1ece068e7 |
312132132432103 has 2 divisors, whose sum is σ = 312132132432104. Its totient is φ = 312132132432102.
The previous prime is 312132132432077. The next prime is 312132132432163. The reversal of 312132132432103 is 301234231231213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312132132432103 - 221 = 312132130334951 is a prime.
It is a super-2 number, since 2×3121321324321032 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312132132432163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156066066216051 + 156066066216052.
It is an arithmetic number, because the mean of its divisors is an integer number (156066066216052).
Almost surely, 2312132132432103 is an apocalyptic number.
312132132432103 is a deficient number, since it is larger than the sum of its proper divisors (1).
312132132432103 is an equidigital number, since it uses as much as digits as its factorization.
312132132432103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 312132132432103 its reverse (301234231231213), we get a palindrome (613366363663316).
The spelling of 312132132432103 in words is "three hundred twelve trillion, one hundred thirty-two billion, one hundred thirty-two million, four hundred thirty-two thousand, one hundred three".
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