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312132132432103 is a prime number
BaseRepresentation
bin100011011111000011110110…
…0111000000110100011100111
31111221011112120222111201012011
41012332013230320012203213
5311402433101400311403
63023503304434535051
7122513542134602134
oct10676075470064347
91457145528451164
10312132132432103
1190500548543235
122b01136b737487
1310521c1a701069
1457113c0bad58b
152614416914a6d
hex11be1ece068e7

312132132432103 has 2 divisors, whose sum is σ = 312132132432104. Its totient is φ = 312132132432102.

The previous prime is 312132132432077. The next prime is 312132132432163. The reversal of 312132132432103 is 301234231231213.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 312132132432103 - 221 = 312132130334951 is a prime.

It is a super-2 number, since 2×3121321324321032 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312132132432163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156066066216051 + 156066066216052.

It is an arithmetic number, because the mean of its divisors is an integer number (156066066216052).

Almost surely, 2312132132432103 is an apocalyptic number.

312132132432103 is a deficient number, since it is larger than the sum of its proper divisors (1).

312132132432103 is an equidigital number, since it uses as much as digits as its factorization.

312132132432103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 312132132432103 its reverse (301234231231213), we get a palindrome (613366363663316).

The spelling of 312132132432103 in words is "three hundred twelve trillion, one hundred thirty-two billion, one hundred thirty-two million, four hundred thirty-two thousand, one hundred three".