Base | Representation |
---|---|
bin | 101101011010111101110… |
… | …101010101011111110011 |
3 | 102001101200221012102022200 |
4 | 231122331311111133303 |
5 | 402114441232214103 |
6 | 10345530354434243 |
7 | 441336331603011 |
oct | 55327565253763 |
9 | 12041627172280 |
10 | 3121331132403 |
11 | aa3827062320 |
12 | 424b27592983 |
13 | 198456732783 |
14 | ab104d458b1 |
15 | 562d64d90a3 |
hex | 2d6bdd557f3 |
3121331132403 has 12 divisors (see below), whose sum is σ = 4918461178488. Its totient is φ = 1891715837760.
The previous prime is 3121331132401. The next prime is 3121331132411. The reversal of 3121331132403 is 3042311331213.
3121331132403 is a `hidden beast` number, since 3 + 1 + 2 + 1 + 331 + 1 + 324 + 0 + 3 = 666.
It is not a de Polignac number, because 3121331132403 - 21 = 3121331132401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3121331132401) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15764298550 + ... + 15764298747.
It is an arithmetic number, because the mean of its divisors is an integer number (409871764874).
Almost surely, 23121331132403 is an apocalyptic number.
3121331132403 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3121331132403 is a deficient number, since it is larger than the sum of its proper divisors (1797130046085).
3121331132403 is a wasteful number, since it uses less digits than its factorization.
3121331132403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31528597314 (or 31528597311 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 3121331132403 its reverse (3042311331213), we get a palindrome (6163642463616).
The spelling of 3121331132403 in words is "three trillion, one hundred twenty-one billion, three hundred thirty-one million, one hundred thirty-two thousand, four hundred three".
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