Base | Representation |
---|---|
bin | 11101000100011101… |
… | …110101100011100101 |
3 | 2222120022121012122121 |
4 | 131010131311203211 |
5 | 1002411120141201 |
6 | 22201140225541 |
7 | 2153332614265 |
oct | 350435654345 |
9 | 88508535577 |
10 | 31213443301 |
11 | 122681a1a37 |
12 | 607139b2b1 |
13 | 2c358b54a1 |
14 | 17216777a5 |
15 | c2a41c9a1 |
hex | 7447758e5 |
31213443301 has 2 divisors, whose sum is σ = 31213443302. Its totient is φ = 31213443300.
The previous prime is 31213443281. The next prime is 31213443307. The reversal of 31213443301 is 10334431213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28057925025 + 3155518276 = 167505^2 + 56174^2 .
It is a cyclic number.
It is not a de Polignac number, because 31213443301 - 211 = 31213441253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31213443307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606721650 + 15606721651.
It is an arithmetic number, because the mean of its divisors is an integer number (15606721651).
Almost surely, 231213443301 is an apocalyptic number.
It is an amenable number.
31213443301 is a deficient number, since it is larger than the sum of its proper divisors (1).
31213443301 is an equidigital number, since it uses as much as digits as its factorization.
31213443301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 31213443301 its reverse (10334431213), we get a palindrome (41547874514).
The spelling of 31213443301 in words is "thirty-one billion, two hundred thirteen million, four hundred forty-three thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •