Base | Representation |
---|---|
bin | 1110001100011100110100… |
… | …00111100000101110010110 |
3 | 11002112001002012111120100221 |
4 | 13012032122013200232112 |
5 | 13042403000412002332 |
6 | 150215322054224554 |
7 | 6401100550536646 |
oct | 706163207405626 |
9 | 132461065446327 |
10 | 31214113000342 |
11 | 9a44916047198 |
12 | 360160735515a |
13 | 145562a87ba1c |
14 | 79cab1da4526 |
15 | 391e3d9b9297 |
hex | 1c639a1e0b96 |
31214113000342 has 4 divisors (see below), whose sum is σ = 46821169500516. Its totient is φ = 15607056500170.
The previous prime is 31214113000313. The next prime is 31214113000391. The reversal of 31214113000342 is 24300031141213.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7803528250084 + ... + 7803528250087.
It is an arithmetic number, because the mean of its divisors is an integer number (11705292375129).
Almost surely, 231214113000342 is an apocalyptic number.
31214113000342 is a deficient number, since it is larger than the sum of its proper divisors (15607056500174).
31214113000342 is a wasteful number, since it uses less digits than its factorization.
31214113000342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15607056500173.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 31214113000342 its reverse (24300031141213), we get a palindrome (55514144141555).
The spelling of 31214113000342 in words is "thirty-one trillion, two hundred fourteen billion, one hundred thirteen million, three hundred forty-two", and thus it is an aban number.
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