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31214113000342 = 215607056500171
BaseRepresentation
bin1110001100011100110100…
…00111100000101110010110
311002112001002012111120100221
413012032122013200232112
513042403000412002332
6150215322054224554
76401100550536646
oct706163207405626
9132461065446327
1031214113000342
119a44916047198
12360160735515a
13145562a87ba1c
1479cab1da4526
15391e3d9b9297
hex1c639a1e0b96

31214113000342 has 4 divisors (see below), whose sum is σ = 46821169500516. Its totient is φ = 15607056500170.

The previous prime is 31214113000313. The next prime is 31214113000391. The reversal of 31214113000342 is 24300031141213.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7803528250084 + ... + 7803528250087.

It is an arithmetic number, because the mean of its divisors is an integer number (11705292375129).

Almost surely, 231214113000342 is an apocalyptic number.

31214113000342 is a deficient number, since it is larger than the sum of its proper divisors (15607056500174).

31214113000342 is a wasteful number, since it uses less digits than its factorization.

31214113000342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15607056500173.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 31214113000342 its reverse (24300031141213), we get a palindrome (55514144141555).

The spelling of 31214113000342 in words is "thirty-one trillion, two hundred fourteen billion, one hundred thirteen million, three hundred forty-two", and thus it is an aban number.

Divisors: 1 2 15607056500171 31214113000342