Base | Representation |
---|---|
bin | 100011011111001000000010… |
… | …1110101111000000011101111 |
3 | 1111221012101211211010012220120 |
4 | 1012332100011311320003233 |
5 | 311403110024122312143 |
6 | 3023511354412220023 |
7 | 122514311315145534 |
oct | 10676200565700357 |
9 | 1457171754105816 |
10 | 312141141213423 |
11 | 90504350791a55 |
12 | 2b01306476a613 |
13 | 10522a24c372b2 |
14 | 57119d742cd8b |
15 | 2614792778383 |
hex | 11be405d780ef |
312141141213423 has 32 divisors (see below), whose sum is σ = 435340499097600. Its totient is φ = 198562201533696.
The previous prime is 312141141213373. The next prime is 312141141213439. The reversal of 312141141213423 is 324312141141213.
It is a de Polignac number, because none of the positive numbers 2k-312141141213423 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312141141213463) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 127409713 + ... + 129836501.
It is an arithmetic number, because the mean of its divisors is an integer number (13604390596800).
Almost surely, 2312141141213423 is an apocalyptic number.
312141141213423 is a deficient number, since it is larger than the sum of its proper divisors (123199357884177).
312141141213423 is a wasteful number, since it uses less digits than its factorization.
312141141213423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2431351.
The product of its digits is 13824, while the sum is 33.
Adding to 312141141213423 its reverse (324312141141213), we get a palindrome (636453282354636).
The spelling of 312141141213423 in words is "three hundred twelve trillion, one hundred forty-one billion, one hundred forty-one million, two hundred thirteen thousand, four hundred twenty-three".
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