Base | Representation |
---|---|
bin | 100011011111001000000100… |
… | …1011111010010001100101001 |
3 | 1111221012102000002020211011121 |
4 | 1012332100021133102030221 |
5 | 311403110140303300131 |
6 | 3023511404435455241 |
7 | 122514312660214300 |
oct | 10676201137221451 |
9 | 1457172002224147 |
10 | 312141202400041 |
11 | 90504382283403 |
12 | 2b013081157521 |
13 | 10522a3480b3b1 |
14 | 5711a015d9437 |
15 | 2614797d12911 |
hex | 11be4097d2329 |
312141202400041 has 12 divisors (see below), whose sum is σ = 363202867433028. Its totient is φ = 267476038637472.
The previous prime is 312141202400029. The next prime is 312141202400117. The reversal of 312141202400041 is 140004202141213.
It can be written as a sum of positive squares in 2 ways, for example, as 126185433766441 + 185955768633600 = 11233229^2 + 13636560^2 .
It is not a de Polignac number, because 312141202400041 - 25 = 312141202400009 is a prime.
It is a super-2 number, since 2×3121412024000412 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312141202399979 and 312141202400015.
It is not an unprimeable number, because it can be changed into a prime (312141202400941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 875574966 + ... + 875931391.
It is an arithmetic number, because the mean of its divisors is an integer number (30266905619419).
Almost surely, 2312141202400041 is an apocalyptic number.
It is an amenable number.
312141202400041 is a deficient number, since it is larger than the sum of its proper divisors (51061665032987).
312141202400041 is a wasteful number, since it uses less digits than its factorization.
312141202400041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1751510008 (or 1751510001 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 312141202400041 its reverse (140004202141213), we get a palindrome (452145404541254).
The spelling of 312141202400041 in words is "three hundred twelve trillion, one hundred forty-one billion, two hundred two million, four hundred thousand, forty-one".
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