Base | Representation |
---|---|
bin | 100011011111001000000100… |
… | …1100010011011001000000001 |
3 | 1111221012102000010210122010002 |
4 | 1012332100021202123020001 |
5 | 311403110141011114131 |
6 | 3023511404505245345 |
7 | 122514313000212563 |
oct | 10676201142331001 |
9 | 1457172003718102 |
10 | 312141203223041 |
11 | 90504382795775 |
12 | 2b013081493855 |
13 | 10522a34a38b8a |
14 | 5711a01771333 |
15 | 2614797e266cb |
hex | 11be40989b201 |
312141203223041 has 8 divisors (see below), whose sum is σ = 322212387628800. Its totient is φ = 302070150900720.
The previous prime is 312141203223023. The next prime is 312141203223043. The reversal of 312141203223041 is 140322302141213.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312141203223041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 312141203222995 and 312141203223013.
It is not an unprimeable number, because it can be changed into a prime (312141203223043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28207046 + ... + 37681823.
It is an arithmetic number, because the mean of its divisors is an integer number (40276548453600).
Almost surely, 2312141203223041 is an apocalyptic number.
312141203223041 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
It is an amenable number.
312141203223041 is a deficient number, since it is larger than the sum of its proper divisors (10071184405759).
312141203223041 is a wasteful number, since it uses less digits than its factorization.
312141203223041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66041719.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 312141203223041 its reverse (140322302141213), we get a palindrome (452463505364254).
The spelling of 312141203223041 in words is "three hundred twelve trillion, one hundred forty-one billion, two hundred three million, two hundred twenty-three thousand, forty-one".
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