Base | Representation |
---|---|
bin | 100011011111001000001010… |
… | …1100000110000110110000111 |
3 | 1111221012102112010210222010111 |
4 | 1012332100111200300312013 |
5 | 311403111043423124221 |
6 | 3023511440443133451 |
7 | 122514320656601452 |
oct | 10676202540606607 |
9 | 1457172463728114 |
10 | 312141404114311 |
11 | 90504476127312 |
12 | 2b013118814287 |
13 | 10522a67545a55 |
14 | 5711a20306499 |
15 | 26147aa8a9be1 |
hex | 11be415830d87 |
312141404114311 has 4 divisors (see below), whose sum is σ = 318030864569352. Its totient is φ = 306251943659272.
The previous prime is 312141404114303. The next prime is 312141404114339. The reversal of 312141404114311 is 113411404141213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 312141404114311 - 23 = 312141404114303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312141404111311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2944730227441 + ... + 2944730227546.
It is an arithmetic number, because the mean of its divisors is an integer number (79507716142338).
Almost surely, 2312141404114311 is an apocalyptic number.
312141404114311 is a deficient number, since it is larger than the sum of its proper divisors (5889460455041).
312141404114311 is an equidigital number, since it uses as much as digits as its factorization.
312141404114311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5889460455040.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 312141404114311 its reverse (113411404141213), we get a palindrome (425552808255524).
The spelling of 312141404114311 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred four million, one hundred fourteen thousand, three hundred eleven".
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