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312141404114311 = 535889460454987
BaseRepresentation
bin100011011111001000001010…
…1100000110000110110000111
31111221012102112010210222010111
41012332100111200300312013
5311403111043423124221
63023511440443133451
7122514320656601452
oct10676202540606607
91457172463728114
10312141404114311
1190504476127312
122b013118814287
1310522a67545a55
145711a20306499
1526147aa8a9be1
hex11be415830d87

312141404114311 has 4 divisors (see below), whose sum is σ = 318030864569352. Its totient is φ = 306251943659272.

The previous prime is 312141404114303. The next prime is 312141404114339. The reversal of 312141404114311 is 113411404141213.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 312141404114311 - 23 = 312141404114303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312141404111311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2944730227441 + ... + 2944730227546.

It is an arithmetic number, because the mean of its divisors is an integer number (79507716142338).

Almost surely, 2312141404114311 is an apocalyptic number.

312141404114311 is a deficient number, since it is larger than the sum of its proper divisors (5889460455041).

312141404114311 is an equidigital number, since it uses as much as digits as its factorization.

312141404114311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5889460455040.

The product of its (nonzero) digits is 4608, while the sum is 31.

Adding to 312141404114311 its reverse (113411404141213), we get a palindrome (425552808255524).

The spelling of 312141404114311 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred four million, one hundred fourteen thousand, three hundred eleven".

Divisors: 1 53 5889460454987 312141404114311