Base | Representation |
---|---|
bin | 100011011111001000001011… |
… | …1001111010101111111011110 |
3 | 1111221012102121011100201011210 |
4 | 1012332100113033111333132 |
5 | 311403111123333233202 |
6 | 3023511443400325250 |
7 | 122514321461153526 |
oct | 10676202717257736 |
9 | 1457172534321153 |
10 | 312141433102302 |
11 | 90504490526431 |
12 | 2b013126473826 |
13 | 10522a705551cb |
14 | 5711a240d0686 |
15 | 26147ad1d3c6c |
hex | 11be4173d5fde |
312141433102302 has 64 divisors (see below), whose sum is σ = 640390633231104. Its totient is φ = 101369552981760.
The previous prime is 312141433102259. The next prime is 312141433102309. The reversal of 312141433102302 is 203201334141213.
It is a self number, because there is not a number n which added to its sum of digits gives 312141433102302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312141433102309) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1234156168 + ... + 1234409060.
It is an arithmetic number, because the mean of its divisors is an integer number (10006103644236).
Almost surely, 2312141433102302 is an apocalyptic number.
312141433102302 is an abundant number, since it is smaller than the sum of its proper divisors (328249200128802).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312141433102302 is a wasteful number, since it uses less digits than its factorization.
312141433102302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 259833.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 312141433102302 its reverse (203201334141213), we get a palindrome (515342767243515).
The spelling of 312141433102302 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred thirty-three million, one hundred two thousand, three hundred two".
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