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312150540151 = 7134469127549
BaseRepresentation
bin1001000101011011001…
…11110011111101110111
31002211201022022102100201
410202231213303331313
520103241014241101
6355222221221331
731360244545552
oct4425547637567
91084638272321
10312150540151
11110422929a1a
12505b6701847
1323588221138
1411172b49699
1581be268e01
hex48ad9f3f77

312150540151 has 8 divisors (see below), whose sum is σ = 316558692000. Its totient is φ = 307742712480.

The previous prime is 312150540133. The next prime is 312150540217. The reversal of 312150540151 is 151045051213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 312150540151 - 229 = 311613669239 is a prime.

It is a super-2 number, since 2×3121505401512 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312150540101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2383525 + ... + 2511073.

It is an arithmetic number, because the mean of its divisors is an integer number (39569836500).

Almost surely, 2312150540151 is an apocalyptic number.

312150540151 is a deficient number, since it is larger than the sum of its proper divisors (4408151849).

312150540151 is a wasteful number, since it uses less digits than its factorization.

312150540151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162089.

The product of its (nonzero) digits is 3000, while the sum is 28.

Adding to 312150540151 its reverse (151045051213), we get a palindrome (463195591364).

The spelling of 312150540151 in words is "three hundred twelve billion, one hundred fifty million, five hundred forty thousand, one hundred fifty-one".

Divisors: 1 71 34469 127549 2447299 9055979 4396486481 312150540151