Base | Representation |
---|---|
bin | 1001000101011011001… |
… | …11110011111101110111 |
3 | 1002211201022022102100201 |
4 | 10202231213303331313 |
5 | 20103241014241101 |
6 | 355222221221331 |
7 | 31360244545552 |
oct | 4425547637567 |
9 | 1084638272321 |
10 | 312150540151 |
11 | 110422929a1a |
12 | 505b6701847 |
13 | 23588221138 |
14 | 11172b49699 |
15 | 81be268e01 |
hex | 48ad9f3f77 |
312150540151 has 8 divisors (see below), whose sum is σ = 316558692000. Its totient is φ = 307742712480.
The previous prime is 312150540133. The next prime is 312150540217. The reversal of 312150540151 is 151045051213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 312150540151 - 229 = 311613669239 is a prime.
It is a super-2 number, since 2×3121505401512 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312150540101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2383525 + ... + 2511073.
It is an arithmetic number, because the mean of its divisors is an integer number (39569836500).
Almost surely, 2312150540151 is an apocalyptic number.
312150540151 is a deficient number, since it is larger than the sum of its proper divisors (4408151849).
312150540151 is a wasteful number, since it uses less digits than its factorization.
312150540151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162089.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 312150540151 its reverse (151045051213), we get a palindrome (463195591364).
The spelling of 312150540151 in words is "three hundred twelve billion, one hundred fifty million, five hundred forty thousand, one hundred fifty-one".
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