312153010441 has 4 divisors (see below), whose sum is σ = 312529552900. Its totient is φ = 311776467984.

The previous prime is 312153010439. The next prime is 312153010459. The reversal of 312153010441 is 144010351213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 144010351213 = 261847 ⋅549979.

It can be written as a sum of positive squares in 2 ways, for example, as 101560129225 + 210592881216 = 318685^2 + 458904^2 .

It is a cyclic number.

It is not a de Polignac number, because 312153010441 - 2¹ = 312153010439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312153710441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188269986 + ... + 188271643.

It is an arithmetic number, because the mean of its divisors is an integer number (78132388225).

Almost surely, 2^312153010441 is an apocalyptic number.

It is an amenable number.

312153010441 is a deficient number, since it is larger than the sum of its proper divisors (376542459).

312153010441 is an equidigital number, since it uses as much as digits as its factorization.

312153010441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 376542458.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 312153010441 its reverse (144010351213), we get a palindrome (456163361654).

The spelling of 312153010441 in words is "three hundred twelve billion, one hundred fifty-three million, ten thousand, four hundred forty-one".