3122103113 has 4 divisors (see below), whose sum is σ = 3122266308. Its totient is φ = 3121939920.

The previous prime is 3122103079. The next prime is 3122103121. The reversal of 3122103113 is 3113012213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3113012213 = 1259 ⋅2472607.

It can be written as a sum of positive squares in 2 ways, for example, as 2161599049 + 960504064 = 46493^2 + 30992^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3122103113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3122103091 and 3122103100.

It is not an unprimeable number, because it can be changed into a prime (3122103163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48398 + ... + 92663.

It is an arithmetic number, because the mean of its divisors is an integer number (780566577).

Almost surely, 2^3122103113 is an apocalyptic number.

It is an amenable number.

3122103113 is a deficient number, since it is larger than the sum of its proper divisors (163195).

3122103113 is a wasteful number, since it uses less digits than its factorization.

3122103113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163194.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 3122103113 is about 55875.7828848957. The cubic root of 3122103113 is about 1461.5569668273.

Adding to 3122103113 its reverse (3113012213), we get a palindrome (6235115326).

The spelling of 3122103113 in words is "three billion, one hundred twenty-two million, one hundred three thousand, one hundred thirteen".