Base | Representation |
---|---|
bin | 100011011111101000110010… |
… | …0001110001001101100010101 |
3 | 1111221110010022100102111201111 |
4 | 1012333101210032021230111 |
5 | 311410233014143042044 |
6 | 3024003542443255021 |
7 | 122522350431010051 |
oct | 10677214416115425 |
9 | 1457403270374644 |
10 | 312211444112149 |
11 | 9053114795834a |
12 | 2b024804b1a471 |
13 | 1052954a055c5a |
14 | 5715186370c61 |
15 | 261650976bb34 |
hex | 11bf464389b15 |
312211444112149 has 2 divisors, whose sum is σ = 312211444112150. Its totient is φ = 312211444112148.
The previous prime is 312211444112077. The next prime is 312211444112167. The reversal of 312211444112149 is 941211444112213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 310844473931524 + 1366970180625 = 17630782^2 + 1169175^2 .
It is a cyclic number.
It is not a de Polignac number, because 312211444112149 - 211 = 312211444110101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312211444112749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156105722056074 + 156105722056075.
It is an arithmetic number, because the mean of its divisors is an integer number (156105722056075).
Almost surely, 2312211444112149 is an apocalyptic number.
It is an amenable number.
312211444112149 is a deficient number, since it is larger than the sum of its proper divisors (1).
312211444112149 is an equidigital number, since it uses as much as digits as its factorization.
312211444112149 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 40.
The spelling of 312211444112149 in words is "three hundred twelve trillion, two hundred eleven billion, four hundred forty-four million, one hundred twelve thousand, one hundred forty-nine".
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