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312212254153 is a prime number
BaseRepresentation
bin1001000101100010100…
…11001110110111001001
31002211212121102211001111
410202301103032313021
520103402314113103
6355232304050321
731361624242012
oct4426123166711
91084777384044
10312212254153
11110454750628
12506133039a1
1323597c4b2b7
141117b012009
1581c48a986d
hex48b14cedc9

312212254153 has 2 divisors, whose sum is σ = 312212254154. Its totient is φ = 312212254152.

The previous prime is 312212254141. The next prime is 312212254177. The reversal of 312212254153 is 351452212213.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 163064131344 + 149148122809 = 403812^2 + 386197^2 .

It is a cyclic number.

It is not a de Polignac number, because 312212254153 - 217 = 312212123081 is a prime.

It is not a weakly prime, because it can be changed into another prime (312212254183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156106127076 + 156106127077.

It is an arithmetic number, because the mean of its divisors is an integer number (156106127077).

Almost surely, 2312212254153 is an apocalyptic number.

It is an amenable number.

312212254153 is a deficient number, since it is larger than the sum of its proper divisors (1).

312212254153 is an equidigital number, since it uses as much as digits as its factorization.

312212254153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 31.

Adding to 312212254153 its reverse (351452212213), we get a palindrome (663664466366).

The spelling of 312212254153 in words is "three hundred twelve billion, two hundred twelve million, two hundred fifty-four thousand, one hundred fifty-three".