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3122140412201 is a prime number
BaseRepresentation
bin101101011011101110000…
…100011111100100101001
3102001110210100000002111112
4231123232010133210221
5402123120421142301
610350142544240105
7441365356426226
oct55335604374451
912043710002445
103122140412201
11aa41019611a8
12425112610035
131985552b4465
14ab18060894d
15563325959bb
hex2d6ee11f929

3122140412201 has 2 divisors, whose sum is σ = 3122140412202. Its totient is φ = 3122140412200.

The previous prime is 3122140412147. The next prime is 3122140412243. The reversal of 3122140412201 is 1022140412213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1619307150400 + 1502833261801 = 1272520^2 + 1225901^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3122140412201 is a prime.

It is a super-3 number, since 3×31221404122013 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (3122170412201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561070206100 + 1561070206101.

It is an arithmetic number, because the mean of its divisors is an integer number (1561070206101).

Almost surely, 23122140412201 is an apocalyptic number.

It is an amenable number.

3122140412201 is a deficient number, since it is larger than the sum of its proper divisors (1).

3122140412201 is an equidigital number, since it uses as much as digits as its factorization.

3122140412201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 3122140412201 its reverse (1022140412213), we get a palindrome (4144280824414).

The spelling of 3122140412201 in words is "three trillion, one hundred twenty-two billion, one hundred forty million, four hundred twelve thousand, two hundred one".