312214041281 has 2 divisors, whose sum is σ = 312214041282. Its totient is φ = 312214041280.

The previous prime is 312214041239. The next prime is 312214041283. The reversal of 312214041281 is 182140412213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 234938937025 + 77275104256 = 484705^2 + 277984^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-312214041281 is a prime.

It is a super-3 number, since 3×312214041281³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 312214041283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (312214041283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156107020640 + 156107020641.

It is an arithmetic number, because the mean of its divisors is an integer number (156107020641).

Almost surely, 2^312214041281 is an apocalyptic number.

It is an amenable number.

312214041281 is a deficient number, since it is larger than the sum of its proper divisors (1).

312214041281 is an equidigital number, since it uses as much as digits as its factorization.

312214041281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 312214041281 its reverse (182140412213), we get a palindrome (494354453494).

The spelling of 312214041281 in words is "three hundred twelve billion, two hundred fourteen million, forty-one thousand, two hundred eighty-one".