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3122220000201 = 31040740000067
BaseRepresentation
bin101101011011110010110…
…100000110001111001001
3102001110222212202120201020
4231123302310012033021
5402123301310001301
610350154510143053
7441400344055221
oct55336264061711
912043885676636
103122220000201
11aa4142880905
124251351b1a89
1319856892c153
14ab18b005081
1556339567436
hex2d6f2d063c9

3122220000201 has 4 divisors (see below), whose sum is σ = 4162960000272. Its totient is φ = 2081480000132.

The previous prime is 3122220000199. The next prime is 3122220000223. The reversal of 3122220000201 is 1020000222213.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3122220000201 - 21 = 3122220000199 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3122220000281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 520370000031 + ... + 520370000036.

It is an arithmetic number, because the mean of its divisors is an integer number (1040740000068).

Almost surely, 23122220000201 is an apocalyptic number.

It is an amenable number.

3122220000201 is a deficient number, since it is larger than the sum of its proper divisors (1040740000071).

3122220000201 is a wasteful number, since it uses less digits than its factorization.

3122220000201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1040740000070.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 3122220000201 its reverse (1020000222213), we get a palindrome (4142220222414).

The spelling of 3122220000201 in words is "three trillion, one hundred twenty-two billion, two hundred twenty million, two hundred one", and thus it is an aban number.

Divisors: 1 3 1040740000067 3122220000201