Base | Representation |
---|---|
bin | 1001000101100011110… |
… | …00110101000100110001 |
3 | 1002211220021222112201220 |
4 | 10202301320311010301 |
5 | 20103412330010001 |
6 | 355233255215253 |
7 | 31362104101164 |
oct | 4426170650461 |
9 | 1084807875656 |
10 | 312222110001 |
11 | 11045a27245a |
12 | 50616677529 |
13 | 23599cbc369 |
14 | 1117c459adb |
15 | 81c56a4c36 |
hex | 48b1e35131 |
312222110001 has 4 divisors (see below), whose sum is σ = 416296146672. Its totient is φ = 208148073332.
The previous prime is 312222109993. The next prime is 312222110021. The reversal of 312222110001 is 100011222213.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 312222110001 - 23 = 312222109993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (312222110021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52037018331 + ... + 52037018336.
It is an arithmetic number, because the mean of its divisors is an integer number (104074036668).
Almost surely, 2312222110001 is an apocalyptic number.
It is an amenable number.
312222110001 is a deficient number, since it is larger than the sum of its proper divisors (104074036671).
312222110001 is a wasteful number, since it uses less digits than its factorization.
312222110001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104074036670.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 312222110001 its reverse (100011222213), we get a palindrome (412233332214).
The spelling of 312222110001 in words is "three hundred twelve billion, two hundred twenty-two million, one hundred ten thousand, one".
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