Base | Representation |
---|---|
bin | 100011011111101110001101… |
… | …1110100110100100000011111 |
3 | 1111221111020102200011021101111 |
4 | 1012333130123310310200133 |
5 | 311410430414242222421 |
6 | 3024013152454322451 |
7 | 122523242556644035 |
oct | 10677343364644037 |
9 | 1457436380137344 |
10 | 312223114414111 |
11 | 905360964a09aa |
12 | 2b026b21359427 |
13 | 1052a689ac2284 |
14 | 5715972288555 |
15 | 261698e0b3ee1 |
hex | 11bf71bd3481f |
312223114414111 has 2 divisors, whose sum is σ = 312223114414112. Its totient is φ = 312223114414110.
The previous prime is 312223114414103. The next prime is 312223114414153. The reversal of 312223114414111 is 111414411322213.
It is a weak prime.
It is an emirp because it is prime and its reverse (111414411322213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312223114414111 - 23 = 312223114414103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312223114414711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156111557207055 + 156111557207056.
It is an arithmetic number, because the mean of its divisors is an integer number (156111557207056).
Almost surely, 2312223114414111 is an apocalyptic number.
312223114414111 is a deficient number, since it is larger than the sum of its proper divisors (1).
312223114414111 is an equidigital number, since it uses as much as digits as its factorization.
312223114414111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4608, while the sum is 31.
Adding to 312223114414111 its reverse (111414411322213), we get a palindrome (423637525736324).
The spelling of 312223114414111 in words is "three hundred twelve trillion, two hundred twenty-three billion, one hundred fourteen million, four hundred fourteen thousand, one hundred eleven".
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