Base | Representation |
---|---|
bin | 1110001100101100000110… |
… | …01010101111010001000001 |
3 | 11002112211021000110220120012 |
4 | 13012112003022233101001 |
5 | 13043021301340424321 |
6 | 150223200153554305 |
7 | 6401511100222451 |
oct | 706260312572101 |
9 | 132484230426505 |
10 | 31222317904961 |
11 | 9a483465474a7 |
12 | 3603117115995 |
13 | 14563376a5681 |
14 | 79d24d969d61 |
15 | 39226de8c05b |
hex | 1c65832af441 |
31222317904961 has 2 divisors, whose sum is σ = 31222317904962. Its totient is φ = 31222317904960.
The previous prime is 31222317904919. The next prime is 31222317904963. The reversal of 31222317904961 is 16940971322213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16492695654400 + 14729622250561 = 4061120^2 + 3837919^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31222317904961 is a prime.
Together with 31222317904963, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31222317904963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15611158952480 + 15611158952481.
It is an arithmetic number, because the mean of its divisors is an integer number (15611158952481).
Almost surely, 231222317904961 is an apocalyptic number.
It is an amenable number.
31222317904961 is a deficient number, since it is larger than the sum of its proper divisors (1).
31222317904961 is an equidigital number, since it uses as much as digits as its factorization.
31222317904961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 50.
The spelling of 31222317904961 in words is "thirty-one trillion, two hundred twenty-two billion, three hundred seventeen million, nine hundred four thousand, nine hundred sixty-one".
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