3122232433 has 4 divisors (see below), whose sum is σ = 3122350308. Its totient is φ = 3122114560.

The previous prime is 3122232431. The next prime is 3122232439. The reversal of 3122232433 is 3342322213.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3342322213 = 17 ⋅196607189.

It can be written as a sum of positive squares in 2 ways, for example, as 730729024 + 2391503409 = 27032^2 + 48903^2 .

It is a cyclic number.

It is not a de Polignac number, because 3122232433 - 2¹ = 3122232431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3122232398 and 3122232407.

It is not an unprimeable number, because it can be changed into a prime (3122232431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1353 + ... + 79033.

It is an arithmetic number, because the mean of its divisors is an integer number (780587577).

Almost surely, 2^3122232433 is an apocalyptic number.

It is an amenable number.

3122232433 is a deficient number, since it is larger than the sum of its proper divisors (117875).

3122232433 is an equidigital number, since it uses as much as digits as its factorization.

3122232433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117874.

The product of its digits is 5184, while the sum is 25.

The square root of 3122232433 is about 55876.9400826495. The cubic root of 3122232433 is about 1461.5771461670.

Adding to 3122232433 its reverse (3342322213), we get a palindrome (6464554646).

The spelling of 3122232433 in words is "three billion, one hundred twenty-two million, two hundred thirty-two thousand, four hundred thirty-three".