Base | Representation |
---|---|
bin | 101101011011110111101… |
… | …010010011101101010111 |
3 | 102001111012112210001112111 |
4 | 231123313222103231113 |
5 | 402123433114220043 |
6 | 10350210533131451 |
7 | 441402352216234 |
oct | 55336752235527 |
9 | 12044175701474 |
10 | 3122301320023 |
11 | aa4184773676 |
12 | 425158489b87 |
13 | 19857c7321a2 |
14 | ab197b3278b |
15 | 5634177c09d |
hex | 2d6f7a93b57 |
3122301320023 has 4 divisors (see below), whose sum is σ = 3123067909248. Its totient is φ = 3121534730800.
The previous prime is 3122301320003. The next prime is 3122301320059. The reversal of 3122301320023 is 3200231032213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3122301320023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3122301319976 and 3122301320003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3122301320003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 383288503 + ... + 383296648.
It is an arithmetic number, because the mean of its divisors is an integer number (780766977312).
Almost surely, 23122301320023 is an apocalyptic number.
3122301320023 is a deficient number, since it is larger than the sum of its proper divisors (766589225).
3122301320023 is an equidigital number, since it uses as much as digits as its factorization.
3122301320023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 766589224.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 3122301320023 its reverse (3200231032213), we get a palindrome (6322532352236).
The spelling of 3122301320023 in words is "three trillion, one hundred twenty-two billion, three hundred one million, three hundred twenty thousand, twenty-three".
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