Base | Representation |
---|---|
bin | 100011011111110010010111… |
… | …0000110101011011101000111 |
3 | 1111221112002101200200200111010 |
4 | 1012333210232012223131013 |
5 | 311411102124310120403 |
6 | 3024021223343413303 |
7 | 122524006205565606 |
oct | 10677445606533507 |
9 | 1457462350620433 |
10 | 312232011020103 |
11 | 90539941392739 |
12 | 2b0287a48b4233 |
13 | 1052b477010c85 |
14 | 5716177a67a3d |
15 | 2616d1016a603 |
hex | 11bf92e1ab747 |
312232011020103 has 16 divisors (see below), whose sum is σ = 434410452403200. Its totient is φ = 199104150906144.
The previous prime is 312232011020087. The next prime is 312232011020107. The reversal of 312232011020103 is 301020110232213.
It is not a de Polignac number, because 312232011020103 - 24 = 312232011020087 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 312232011020103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312232011020107) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44140098 + ... + 50722896.
It is an arithmetic number, because the mean of its divisors is an integer number (27150653275200).
Almost surely, 2312232011020103 is an apocalyptic number.
312232011020103 is a deficient number, since it is larger than the sum of its proper divisors (122178441383097).
312232011020103 is a wasteful number, since it uses less digits than its factorization.
312232011020103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7270238.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 312232011020103 its reverse (301020110232213), we get a palindrome (613252121252316).
The spelling of 312232011020103 in words is "three hundred twelve trillion, two hundred thirty-two billion, eleven million, twenty thousand, one hundred three".
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