Base | Representation |
---|---|
bin | 100011011111110010010111… |
… | …0000111000011111000010101 |
3 | 1111221112002101200212202201112 |
4 | 1012333210232013003320111 |
5 | 311411102124321321044 |
6 | 3024021223345504405 |
7 | 122524006206463361 |
oct | 10677445607037025 |
9 | 1457462350782645 |
10 | 312232011120149 |
11 | 9053994145091a |
12 | 2b0287a4942105 |
13 | 1052b477047683 |
14 | 5716177a922a1 |
15 | 2616d1018a09e |
hex | 11bf92e1c3e15 |
312232011120149 has 2 divisors, whose sum is σ = 312232011120150. Its totient is φ = 312232011120148.
The previous prime is 312232011120101. The next prime is 312232011120203. The reversal of 312232011120149 is 941021110232213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 284999999455249 + 27232011664900 = 16881943^2 + 5218430^2 .
It is a cyclic number.
It is not a de Polignac number, because 312232011120149 - 28 = 312232011119893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312232011120749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156116005560074 + 156116005560075.
It is an arithmetic number, because the mean of its divisors is an integer number (156116005560075).
Almost surely, 2312232011120149 is an apocalyptic number.
It is an amenable number.
312232011120149 is a deficient number, since it is larger than the sum of its proper divisors (1).
312232011120149 is an equidigital number, since it uses as much as digits as its factorization.
312232011120149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 312232011120149 in words is "three hundred twelve trillion, two hundred thirty-two billion, eleven million, one hundred twenty thousand, one hundred forty-nine".
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