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3122514113 = 10330315671
BaseRepresentation
bin1011101000011101…
…1100100011000001
322001121120011002212
42322013130203001
522343330422423
61233502151505
7140243634455
oct27207344301
98047504085
103122514113
11136263a084
12731882595
133a9bab8b4
142189b8665
151341e4578
hexba1dc8c1

3122514113 has 4 divisors (see below), whose sum is σ = 3152829888. Its totient is φ = 3092198340.

The previous prime is 3122514107. The next prime is 3122514139. The reversal of 3122514113 is 3114152213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3122514113 - 28 = 3122513857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3122514103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15157733 + ... + 15157938.

It is an arithmetic number, because the mean of its divisors is an integer number (788207472).

Almost surely, 23122514113 is an apocalyptic number.

It is an amenable number.

3122514113 is a deficient number, since it is larger than the sum of its proper divisors (30315775).

3122514113 is a wasteful number, since it uses less digits than its factorization.

3122514113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30315774.

The product of its digits is 720, while the sum is 23.

The square root of 3122514113 is about 55879.4605646833. The cubic root of 3122514113 is about 1461.6210981233.

Adding to 3122514113 its reverse (3114152213), we get a palindrome (6236666326).

The spelling of 3122514113 in words is "three billion, one hundred twenty-two million, five hundred fourteen thousand, one hundred thirteen".

Divisors: 1 103 30315671 3122514113