Base | Representation |
---|---|
bin | 1110001100111010011010… |
… | …00111111101000110000111 |
3 | 11002120120002110211200202201 |
4 | 13012131031013331012013 |
5 | 13043133020242440403 |
6 | 150230510420215331 |
7 | 6402202353520063 |
oct | 706351507750607 |
9 | 132516073750681 |
10 | 31230001140103 |
11 | 9a5062952a807 |
12 | 360470023a547 |
13 | 1456c903cac5c |
14 | 79d77c138aa3 |
15 | 39256d76621d |
hex | 1c674d1fd187 |
31230001140103 has 4 divisors (see below), whose sum is σ = 31402542583048. Its totient is φ = 31057459697160.
The previous prime is 31230001140017. The next prime is 31230001140109. The reversal of 31230001140103 is 30104110003213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31230001140103 - 221 = 31229999042951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31230001140109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86270721201 + ... + 86270721562.
It is an arithmetic number, because the mean of its divisors is an integer number (7850635645762).
Almost surely, 231230001140103 is an apocalyptic number.
31230001140103 is a deficient number, since it is larger than the sum of its proper divisors (172541442945).
31230001140103 is a wasteful number, since it uses less digits than its factorization.
31230001140103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 172541442944.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 31230001140103 its reverse (30104110003213), we get a palindrome (61334111143316).
The spelling of 31230001140103 in words is "thirty-one trillion, two hundred thirty billion, one million, one hundred forty thousand, one hundred three".
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