Base | Representation |
---|---|
bin | 1110001100111010011010… |
… | …10000010100011111101111 |
3 | 11002120120002121222002222221 |
4 | 13012131031100110133233 |
5 | 13043133021323124403 |
6 | 150230510535220211 |
7 | 6402202411252501 |
oct | 706351520243757 |
9 | 132516077862887 |
10 | 31230003333103 |
11 | 9a5062a798403 |
12 | 3604700b17667 |
13 | 1456c909b81a3 |
14 | 79d77c549d71 |
15 | 39256da4adbd |
hex | 1c674d4147ef |
31230003333103 has 4 divisors (see below), whose sum is σ = 31521872523240. Its totient is φ = 30938134142968.
The previous prime is 31230003333041. The next prime is 31230003333127. The reversal of 31230003333103 is 30133330003213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31230003333103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31230603333103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 145934594908 + ... + 145934595121.
It is an arithmetic number, because the mean of its divisors is an integer number (7880468130810).
Almost surely, 231230003333103 is an apocalyptic number.
31230003333103 is a deficient number, since it is larger than the sum of its proper divisors (291869190137).
31230003333103 is a wasteful number, since it uses less digits than its factorization.
31230003333103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 291869190136.
The product of its (nonzero) digits is 4374, while the sum is 25.
Adding to 31230003333103 its reverse (30133330003213), we get a palindrome (61363333336316).
The spelling of 31230003333103 in words is "thirty-one trillion, two hundred thirty billion, three million, three hundred thirty-three thousand, one hundred three".
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