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31230014041011 = 310410004680337
BaseRepresentation
bin1110001100111010011011…
…11001001010101110110011
311002120120010101010010111010
413012131031321022232303
513043133032043303021
6150230512000522003
76402202601261052
oct706351571125663
9132516111103433
1031230014041011
119a50635841415
123604704620303
131456c92c97026
1479d77db36399
1539256e963976
hex1c674de4abb3

31230014041011 has 4 divisors (see below), whose sum is σ = 41640018721352. Its totient is φ = 20820009360672.

The previous prime is 31230014040859. The next prime is 31230014041019. The reversal of 31230014041011 is 11014041003213.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 31230014041011 - 239 = 30680258227123 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31230014041019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5205002340166 + ... + 5205002340171.

It is an arithmetic number, because the mean of its divisors is an integer number (10410004680338).

Almost surely, 231230014041011 is an apocalyptic number.

31230014041011 is a deficient number, since it is larger than the sum of its proper divisors (10410004680341).

31230014041011 is a wasteful number, since it uses less digits than its factorization.

31230014041011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10410004680340.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 31230014041011 its reverse (11014041003213), we get a palindrome (42244055044224).

The spelling of 31230014041011 in words is "thirty-one trillion, two hundred thirty billion, fourteen million, forty-one thousand, eleven".

Divisors: 1 3 10410004680337 31230014041011