Base | Representation |
---|---|
bin | 100011100000010010111111… |
… | …1111011001111101011111111 |
3 | 1111221202210022112112221020200 |
4 | 1013000211333323033223333 |
5 | 311413224201411344411 |
6 | 3024113334451014543 |
7 | 122532040152550431 |
oct | 10700457773175377 |
9 | 1457683275487220 |
10 | 312302103231231 |
11 | 9056663a636353 |
12 | 2b03a2a659a453 |
13 | 10534c675a2b09 |
14 | 5719706a04651 |
15 | 2618a638e2e56 |
hex | 11c097fecfaff |
312302103231231 has 6 divisors (see below), whose sum is σ = 451103038000680. Its totient is φ = 208201402154148.
The previous prime is 312302103231229. The next prime is 312302103231233. The reversal of 312302103231231 is 132132301203213.
312302103231231 is a `hidden beast` number, since 3 + 1 + 2 + 3 + 0 + 210 + 323 + 123 + 1 = 666.
It is an interprime number because it is at equal distance from previous prime (312302103231229) and next prime (312302103231233).
It is not a de Polignac number, because 312302103231231 - 21 = 312302103231229 is a prime.
It is a super-2 number, since 2×3123021032312312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312302103231195 and 312302103231204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312302103231233) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 17350116846171 + ... + 17350116846188.
It is an arithmetic number, because the mean of its divisors is an integer number (75183839666780).
Almost surely, 2312302103231231 is an apocalyptic number.
312302103231231 is a deficient number, since it is larger than the sum of its proper divisors (138800934769449).
312302103231231 is a wasteful number, since it uses less digits than its factorization.
312302103231231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34700233692365 (or 34700233692362 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 312302103231231 its reverse (132132301203213), we get a palindrome (444434404434444).
The spelling of 312302103231231 in words is "three hundred twelve trillion, three hundred two billion, one hundred three million, two hundred thirty-one thousand, two hundred thirty-one".
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