Base | Representation |
---|---|
bin | 100011100000100001000111… |
… | …1100111110011101001000000 |
3 | 1111221212200121011020121011211 |
4 | 1013001002033213303221000 |
5 | 311414223304410422034 |
6 | 3024135312123415504 |
7 | 122534162545336033 |
oct | 10701021747635100 |
9 | 1457780534217154 |
10 | 312332431342144 |
11 | 90578493003a24 |
12 | 2b04414b384594 |
13 | 10537a8b928b85 |
14 | 571ad8285d01a |
15 | 261973b22ed64 |
hex | 11c108f9f3a40 |
312332431342144 has 14 divisors (see below), whose sum is σ = 619784668444694. Its totient is φ = 156166215671040.
The previous prime is 312332431342121. The next prime is 312332431342201. The reversal of 312332431342144 is 441243134233213.
It can be written as a sum of positive squares in only one way, i.e., 296667553921600 + 15664877420544 = 17224040^2 + 3957888^2 .
It is a super-2 number, since 2×3123324313421442 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312332431342097 and 312332431342106.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2440097119797 + ... + 2440097119924.
Almost surely, 2312332431342144 is an apocalyptic number.
It is an amenable number.
312332431342144 is a deficient number, since it is larger than the sum of its proper divisors (307452237102550).
312332431342144 is an equidigital number, since it uses as much as digits as its factorization.
312332431342144 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4880194239733 (or 4880194239723 counting only the distinct ones).
The product of its digits is 497664, while the sum is 40.
Adding to 312332431342144 its reverse (441243134233213), we get a palindrome (753575565575357).
The spelling of 312332431342144 in words is "three hundred twelve trillion, three hundred thirty-two billion, four hundred thirty-one million, three hundred forty-two thousand, one hundred forty-four".
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