312332441030242 has 4 divisors (see below), whose sum is σ = 468498661545366. Its totient is φ = 156166220515120.

The previous prime is 312332441030237. The next prime is 312332441030263. The reversal of 312332441030242 is 242030144233213.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 201653603829441 + 110678837200801 = 14200479^2 + 10520401^2 .

It is a super-3 number, since 3×312332441030242³ (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 312332441030198 and 312332441030207.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78083110257559 + ... + 78083110257562.

Almost surely, 2^{312332441030242} is an apocalyptic number.

312332441030242 is a deficient number, since it is larger than the sum of its proper divisors (156166220515124).

312332441030242 is a wasteful number, since it uses less digits than its factorization.

312332441030242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156166220515123.

The product of its (nonzero) digits is 82944, while the sum is 34.

Adding to 312332441030242 its reverse (242030144233213), we get a palindrome (554362585263455).

The spelling of 312332441030242 in words is "three hundred twelve trillion, three hundred thirty-two billion, four hundred forty-one million, thirty thousand, two hundred forty-two".