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312333311041342 = 2156166655520671
BaseRepresentation
bin100011100000100001100010…
…0000011100101111100111110
31111221212202212110112221121121
41013001003010003211330332
5311414232110111310332
63024135535310421154
7122534223416553523
oct10701030403457476
91457782773487547
10312333311041342
11905788a462aa58
122b044355b017ba
1310537b9bc65246
14571b02761314a
15261978d59b797
hex11c10c40e5f3e

312333311041342 has 4 divisors (see below), whose sum is σ = 468499966562016. Its totient is φ = 156166655520670.

The previous prime is 312333311041333. The next prime is 312333311041421. The reversal of 312333311041342 is 243140113333213.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 312333311041298 and 312333311041307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78083327760334 + ... + 78083327760337.

It is an arithmetic number, because the mean of its divisors is an integer number (117124991640504).

Almost surely, 2312333311041342 is an apocalyptic number.

312333311041342 is a deficient number, since it is larger than the sum of its proper divisors (156166655520674).

312333311041342 is a wasteful number, since it uses less digits than its factorization.

312333311041342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156166655520673.

The product of its (nonzero) digits is 46656, while the sum is 34.

Adding to 312333311041342 its reverse (243140113333213), we get a palindrome (555473424374555).

The spelling of 312333311041342 in words is "three hundred twelve trillion, three hundred thirty-three billion, three hundred eleven million, forty-one thousand, three hundred forty-two".

Divisors: 1 2 156166655520671 312333311041342