Base | Representation |
---|---|
bin | 101101011100111100001… |
… | …000010101100010011011 |
3 | 102001121011121022012120021 |
4 | 231130330020111202123 |
5 | 402133311202330043 |
6 | 10350520530211311 |
7 | 441443001206356 |
oct | 55347410254233 |
9 | 12047147265507 |
10 | 3123450042523 |
11 | aa4714136908 |
12 | 425419123b37 |
13 | 198703711945 |
14 | ab26651529d |
15 | 563ac5393ed |
hex | 2d73c21589b |
3123450042523 has 2 divisors, whose sum is σ = 3123450042524. Its totient is φ = 3123450042522.
The previous prime is 3123450042467. The next prime is 3123450042539. The reversal of 3123450042523 is 3252400543213.
3123450042523 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3123450042523 - 237 = 2986011089051 is a prime.
It is not a weakly prime, because it can be changed into another prime (3123450042593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561725021261 + 1561725021262.
It is an arithmetic number, because the mean of its divisors is an integer number (1561725021262).
Almost surely, 23123450042523 is an apocalyptic number.
3123450042523 is a deficient number, since it is larger than the sum of its proper divisors (1).
3123450042523 is an equidigital number, since it uses as much as digits as its factorization.
3123450042523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 3123450042523 its reverse (3252400543213), we get a palindrome (6375850585736).
The spelling of 3123450042523 in words is "three trillion, one hundred twenty-three billion, four hundred fifty million, forty-two thousand, five hundred twenty-three".
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