Base | Representation |
---|---|
bin | 101111010101000010001… |
… | …011011101010111101101 |
3 | 102111221000101102100210021 |
4 | 233111002023131113231 |
5 | 411241404014340323 |
6 | 10530044315042141 |
7 | 453656342322103 |
oct | 57250213352755 |
9 | 12457011370707 |
10 | 3252400543213 |
11 | 1044376353638 |
12 | 446406440351 |
13 | 1a7914037a63 |
14 | b35ba469c73 |
15 | 5990819005d |
hex | 2f5422dd5ed |
3252400543213 has 4 divisors (see below), whose sum is σ = 3282796810080. Its totient is φ = 3222004276348.
The previous prime is 3252400543207. The next prime is 3252400543303. The reversal of 3252400543213 is 3123450042523.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3252400543213 - 225 = 3252366988781 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3252400543813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15198133273 + ... + 15198133486.
It is an arithmetic number, because the mean of its divisors is an integer number (820699202520).
Almost surely, 23252400543213 is an apocalyptic number.
It is an amenable number.
3252400543213 is a deficient number, since it is larger than the sum of its proper divisors (30396266867).
3252400543213 is a wasteful number, since it uses less digits than its factorization.
3252400543213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30396266866.
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 3252400543213 its reverse (3123450042523), we get a palindrome (6375850585736).
The spelling of 3252400543213 in words is "three trillion, two hundred fifty-two billion, four hundred million, five hundred forty-three thousand, two hundred thirteen".
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