Base | Representation |
---|---|
bin | 1110001101001101110110… |
… | …11000111010010011111101 |
3 | 11002121120001001022012202102 |
4 | 13012212323120322103331 |
5 | 13043320410344413001 |
6 | 150235354355034445 |
7 | 6403022152133546 |
oct | 706467330722375 |
9 | 132546031265672 |
10 | 31240441013501 |
11 | 9a54aa6574155 |
12 | 360673459ba25 |
13 | 1457c6527aa35 |
14 | 7a008c8814cd |
15 | 392980061e6b |
hex | 1c69bb63a4fd |
31240441013501 has 2 divisors, whose sum is σ = 31240441013502. Its totient is φ = 31240441013500.
The previous prime is 31240441013479. The next prime is 31240441013519. The reversal of 31240441013501 is 10531014404213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23934853690276 + 7305587323225 = 4892326^2 + 2702885^2 .
It is a cyclic number.
It is not a de Polignac number, because 31240441013501 - 26 = 31240441013437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31240441013801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15620220506750 + 15620220506751.
It is an arithmetic number, because the mean of its divisors is an integer number (15620220506751).
Almost surely, 231240441013501 is an apocalyptic number.
It is an amenable number.
31240441013501 is a deficient number, since it is larger than the sum of its proper divisors (1).
31240441013501 is an equidigital number, since it uses as much as digits as its factorization.
31240441013501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 31240441013501 its reverse (10531014404213), we get a palindrome (41771455417714).
The spelling of 31240441013501 in words is "thirty-one trillion, two hundred forty billion, four hundred forty-one million, thirteen thousand, five hundred one".
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