Base | Representation |
---|---|
bin | 1110001101001101110111… |
… | …01000100011000011100111 |
3 | 11002121120001100000110121002 |
4 | 13012212323220203003213 |
5 | 13043320412422100201 |
6 | 150235355022543515 |
7 | 6403022232025253 |
oct | 706467350430347 |
9 | 132546040013532 |
10 | 31240445112551 |
11 | 9a54aa89138a4 |
12 | 3606735a37b9b |
13 | 1457c660846cc |
14 | 7a008d22b263 |
15 | 3929805c176b |
hex | 1c69bba230e7 |
31240445112551 has 8 divisors (see below), whose sum is σ = 32504509370880. Its totient is φ = 29988834689632.
The previous prime is 31240445112511. The next prime is 31240445112553. The reversal of 31240445112551 is 15521154404213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31240445112551 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31240445112553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3113453735 + ... + 3113463768.
It is an arithmetic number, because the mean of its divisors is an integer number (4063063671360).
Almost surely, 231240445112551 is an apocalyptic number.
31240445112551 is a deficient number, since it is larger than the sum of its proper divisors (1264064258329).
31240445112551 is a wasteful number, since it uses less digits than its factorization.
31240445112551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6226917705.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 31240445112551 its reverse (15521154404213), we get a palindrome (46761599516764).
The spelling of 31240445112551 in words is "thirty-one trillion, two hundred forty billion, four hundred forty-five million, one hundred twelve thousand, five hundred fifty-one".
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