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3124113140143 = 21136563404951
BaseRepresentation
bin101101011101100011101…
…001110110100110101111
3102001122212211001001111101
4231131203221312212233
5402141140430441033
610351110414503531
7441465302353522
oct55354351664657
912048784031441
103124113140143
11aa4a24470976
12425583204ba7
131987aac003b8
14ab2ca604bb9
15563ea86c97d
hex2d763a769af

3124113140143 has 8 divisors (see below), whose sum is σ = 3139012964736. Its totient is φ = 3109214199000.

The previous prime is 3124113140119. The next prime is 3124113140173. The reversal of 3124113140143 is 3410413114213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3124113140143 - 241 = 925089884591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3124113140173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7512318 + ... + 7917268.

It is an arithmetic number, because the mean of its divisors is an integer number (392376620592).

Almost surely, 23124113140143 is an apocalyptic number.

3124113140143 is a deficient number, since it is larger than the sum of its proper divisors (14899824593).

3124113140143 is a wasteful number, since it uses less digits than its factorization.

3124113140143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 441725.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 3124113140143 its reverse (3410413114213), we get a palindrome (6534526254356).

The spelling of 3124113140143 in words is "three trillion, one hundred twenty-four billion, one hundred thirteen million, one hundred forty thousand, one hundred forty-three".

Divisors: 1 211 36563 404951 7714793 85444661 14806223413 3124113140143