Base | Representation |
---|---|
bin | 100011100001000110110011… |
… | …0010110100110001000000111 |
3 | 1111222011102110001110010022101 |
4 | 1013002031212112212020013 |
5 | 311422040011343434421 |
6 | 3024240413020412531 |
7 | 122543055613111423 |
oct | 10702154626461007 |
9 | 1458142401403271 |
10 | 312413343343111 |
11 | 905a983379990a |
12 | 2b0579706a7147 |
13 | 105425b499991a |
14 | 5720c5a799b83 |
15 | 261b8c47eb191 |
hex | 11c23665a6207 |
312413343343111 has 2 divisors, whose sum is σ = 312413343343112. Its totient is φ = 312413343343110.
The previous prime is 312413343343103. The next prime is 312413343343121. The reversal of 312413343343111 is 111343343314213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312413343343111 - 23 = 312413343343103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312413343343121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156206671671555 + 156206671671556.
It is an arithmetic number, because the mean of its divisors is an integer number (156206671671556).
Almost surely, 2312413343343111 is an apocalyptic number.
312413343343111 is a deficient number, since it is larger than the sum of its proper divisors (1).
312413343343111 is an equidigital number, since it uses as much as digits as its factorization.
312413343343111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 93312, while the sum is 37.
Adding to 312413343343111 its reverse (111343343314213), we get a palindrome (423756686657324).
The spelling of 312413343343111 in words is "three hundred twelve trillion, four hundred thirteen billion, three hundred forty-three million, three hundred forty-three thousand, one hundred eleven".
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