Base | Representation |
---|---|
bin | 101101011101100100111… |
… | …001011100000110111010 |
3 | 102001122221021022000010121 |
4 | 231131210321130012322 |
5 | 402141211301100010 |
6 | 10351112442003454 |
7 | 441465644605540 |
oct | 55354471340672 |
9 | 12048837260117 |
10 | 3124134003130 |
11 | aa4a35220608 |
12 | 42558a1a658a |
13 | 1987b232656a |
14 | ab2cd2b5d90 |
15 | 563ec5de3da |
hex | 2d764e5c1ba |
3124134003130 has 32 divisors (see below), whose sum is σ = 6634105758720. Its totient is φ = 1036579023360.
The previous prime is 3124134003127. The next prime is 3124134003131. The reversal of 3124134003130 is 313004314213.
It is a junction number, because it is equal to n+sod(n) for n = 3124134003095 and 3124134003104.
It is not an unprimeable number, because it can be changed into a prime (3124134003131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 719844375 + ... + 719848714.
It is an arithmetic number, because the mean of its divisors is an integer number (207315804960).
Almost surely, 23124134003130 is an apocalyptic number.
3124134003130 is an abundant number, since it is smaller than the sum of its proper divisors (3509971755590).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3124134003130 is a wasteful number, since it uses less digits than its factorization.
3124134003130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1439693134.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 3124134003130 its reverse (313004314213), we get a palindrome (3437138317343).
The spelling of 3124134003130 in words is "three trillion, one hundred twenty-four billion, one hundred thirty-four million, three thousand, one hundred thirty".
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