Base | Representation |
---|---|
bin | 100011100001000111001011… |
… | …0000110011101100101111111 |
3 | 1111222011111111212211001112001 |
4 | 1013002032112012131211333 |
5 | 311422043131432421343 |
6 | 3024241024314323131 |
7 | 122543114511132256 |
oct | 10702162606354577 |
9 | 1458144455731461 |
10 | 312414144420223 |
11 | 905aa1049a5a0a |
12 | 2b057b54a294a7 |
13 | 105426b1938b51 |
14 | 5720cd4d2579d |
15 | 261b91ecd744d |
hex | 11c239619d97f |
312414144420223 has 2 divisors, whose sum is σ = 312414144420224. Its totient is φ = 312414144420222.
The previous prime is 312414144420193. The next prime is 312414144420233. The reversal of 312414144420223 is 322024441414213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312414144420223 - 29 = 312414144419711 is a prime.
It is a super-2 number, since 2×3124141444202232 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312414144420233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156207072210111 + 156207072210112.
It is an arithmetic number, because the mean of its divisors is an integer number (156207072210112).
Almost surely, 2312414144420223 is an apocalyptic number.
312414144420223 is a deficient number, since it is larger than the sum of its proper divisors (1).
312414144420223 is an equidigital number, since it uses as much as digits as its factorization.
312414144420223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 147456, while the sum is 37.
Adding to 312414144420223 its reverse (322024441414213), we get a palindrome (634438585834436).
The spelling of 312414144420223 in words is "three hundred twelve trillion, four hundred fourteen billion, one hundred forty-four million, four hundred twenty thousand, two hundred twenty-three".
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